What is the solution for (x^2-4)(dy)/(dx)+2xy=3x^2 ?

The solution for (x^2-4)(dy)/(dx)+2xy=3x^2 is y=(x^3)/(x^2-4)+(c_{1})/(x^2-4)

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(x^2-4)(dy)/(dx)+2xy=3x^2

(x^{2} - 4) \frac{d y}{d x} + 2 x y = 3 x^{2}

y = \frac{x ^{3}}{x ^{2} - 4} + \frac{c _{1}}{x ^{2} - 4}

Solution steps

(x^{2} - 4) \frac{d y}{d x} + 2 x y = 3 x^{2}

Solve linear ODE:

y = \frac{x ^{3}}{x ^{2} - 4} + \frac{c _{1}}{x ^{2} - 4}

y = \frac{x ^{3}}{x ^{2} - 4} + \frac{c _{1}}{x ^{2} - 4}

\frac{1}{( s ^{2} + 4 ) ^{2}}

\frac{d}{d t} (5 t^{- 3})

\int_{- 1}^{1} e^{y} - y^{2} + 2 d y

\frac{\partial}{\partial y} (tan (3 x - 2 y + 1))

\frac{s + 7}{s ^{2} + 8 s + 25}

What is the solution for (x^2-4)(dy)/(dx)+2xy=3x^2 ?
The solution for (x^2-4)(dy)/(dx)+2xy=3x^2 is y=(x^3)/(x^2-4)+(c_{1})/(x^2-4)