What is inverse oflaplace 5t ?

The answer to inverse oflaplace 5t is 5\delta'(t)

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inverse oflaplace 5t

inverse laplace

5 t

5 δ' (t)

Solution steps

L^{- 1} {5 t}

Use the constant multiplication property of Inverse Laplace Transform:

For function

f (t)

and constant

a : L^{- 1} {a \cdot f (t)} = a \cdot L^{- 1} {f (t)}

= 5 L^{- 1} {t}

L^{- 1} {t} : δ^{'} (t)

= 5 δ^{^{'}} (t)

\frac{\partial}{\partial y} (\frac{y}{1 + x ^{2} y ^{2}})

\int_{π}^{2 π} x d x

\int \frac{- 1}{1 - ( 4 t + 1 ) ^{2}} d t

e^{x^{2} - 1}

x \to 0 lim (ln (20))

What is inverse oflaplace 5t ?
The answer to inverse oflaplace 5t is 5\delta'(t)