What is area y=1,x=y^{5/2},[0,1] ?

The answer to area y=1,x=y^{5/2},[0,1] is 2/7

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area y=1,x=y^{5/2},[0,1]

area

y = 1, x = y^{\frac{5}{2}}, [0, 1]

\frac{2}{7}

Decimal Notation

0.28571 \dots

Solution steps

Isolate

y

for

Apply the area formula:

Solve

The area is:

= \frac{2}{7}

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x \to 1 lim (ln (x) - ln (x - 1))

x \to 0 lim (\frac{x}{x ^{2} + y ^{2}})

\int \frac{1}{x ^{2} + 8} d x

\int \frac{1}{x 9 x ^{2} + 1} d x

What is area y=1,x=y^{5/2},[0,1] ?
The answer to area y=1,x=y^{5/2},[0,1] is 2/7