What is the solution for (dy)/(dx)x+y=(xy)^{3/2} ?

The solution for (dy)/(dx)x+y=(xy)^{3/2} is y= 4/(x^3-4c_{1)x^2+4c_{1}^2x}

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(dy)/(dx)x+y=(xy)^{3/2}

\frac{d y}{d x} x + y = (x y)^{\frac{3}{2}}

y = \frac{4}{x ^{3} - 4 c _{1} x ^{2} + 4 c _{1}^{2} x}

Solution steps

\frac{d y}{d x} x + y = (x y)^{\frac{3}{2}}

Solve Bernoulli ODE:

y = \frac{4}{x ^{3} - 4 c _{1} x ^{2} + 4 c _{1}^{2} x}

y = \frac{4}{x ^{3} - 4 c _{1} x ^{2} + 4 c _{1}^{2} x}

\int \frac{1}{1 + 8 x} d x

\frac{d}{d x} (6^{s i n (π x)})

\frac{\partial}{\partial x} (ln (7 y e^{x y}))

f (x) = \frac{4 x}{x + 2}, (6, 3)

\int (- \frac{3}{x} + 3 e^{x}) d x

What is the solution for (dy)/(dx)x+y=(xy)^{3/2} ?
The solution for (dy)/(dx)x+y=(xy)^{3/2} is y= 4/(x^3-4c_{1)x^2+4c_{1}^2x}