What is the derivative of-x^2+2x+3 ?

The derivative of-x^2+2x+3 is -2x+2

What is the first derivative of-x^2+2x+3 ?

The first derivative of-x^2+2x+3 is -2x+2

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\frac{d}{d x} (- x^{2} + 2 x + 3)

- 2 x + 2

Solution steps

\frac{d}{d x} (- x^{2} + 2 x + 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (x^{2}) + \frac{d}{d x} (2 x) + \frac{d}{d x} (3)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (3) = 0

= - 2 x + 2 + 0

Simplify

= - 2 x + 2

\int 2 t + 1 d t

y = ln (1 - x^{2})

\int_{0}^{y} 0.5 d x

4 - x^{2}

f (x) = cos (sin (tan (π x)))

What is the derivative of-x^2+2x+3 ?
The derivative of-x^2+2x+3 is -2x+2
What is the first derivative of-x^2+2x+3 ?
The first derivative of-x^2+2x+3 is -2x+2