What is the derivative of (x-1^2+1) ?

The derivative of (x-1^2+1) is 2x-2

What is the first derivative of (x-1^2+1) ?

The first derivative of (x-1^2+1) is 2x-2

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\frac{d}{d x} ((x - 1)^{2} + 1)

2 x - 2

Solution steps

\frac{d}{d x} ((x - 1)^{2} + 1)

Simplify

(x - 1)^{2} + 1 : x^{2} - 2 x + 2

= \frac{d}{d x} (x^{2} - 2 x + 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (2 x) + \frac{d}{d x} (2)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (2) = 0

= 2 x - 2 + 0

Simplify

= 2 x - 2

\frac{\partial}{\partial x} (cos (y e^{x \cdot y}))

\int [1 + \frac{1}{( x + 1 ) ^{2}}] d x

x \to 2 lim (4 - x)

y = \frac{x ^{5}}{3 - x ^{4}}

\frac{\partial}{\partial y} (ln (2 x^{2} + y^{2}))

What is the derivative of (x-1^2+1) ?
The derivative of (x-1^2+1) is 2x-2
What is the first derivative of (x-1^2+1) ?
The first derivative of (x-1^2+1) is 2x-2