What is the tangent of 2x^2-2x-4,\at x=1 ?

The tangent of 2x^2-2x-4,\at x=1 is y=2x-6

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tangent of 2x^2-2x-4,\at x=1

tangent of

2 x^{2} - 2 x - 4, at x = 1

y = 2 x - 6

Solution steps

Find the tangent point:

(1, - 4)

Find the slope of

y = 2 x^{2} - 2 x - 4 : \frac{d y}{d x} = 4 x - 2

Compute the slope of

y = 2 x^{2} - 2 x - 4

x = 1 : m = 2

Find the line with slope m=

2

and passing through

(1, - 4) : y = 2 x - 6

y = 2 x - 6

\frac{cos ( x )}{x ^{5}}

\frac{d}{d x} (\frac{x}{6 - x})

y = 3 x^{2} + 12 x + 6

x \to 2 lim (8 - 3 x + 12 x^{2})

\frac{d}{d x} (\frac{56}{x ^{9}})

What is the tangent of 2x^2-2x-4,\at x=1 ?
The tangent of 2x^2-2x-4,\at x=1 is y=2x-6