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Popular >

f(x)=log_{1/5}(x^2-x-12)+6

Solution

f (x) = lo g_{\frac{1}{5}} (x^{2} - x - 12) + 6

Solution

Domain : x < - 3 or x > 4

Range : - \infty < f (x) < \infty

X Intercepts : (\frac{1 + 62549}{2}, 0), (\frac{1 - 62549}{2}, 0)

Extreme Points : None

+1

Interval Notation

Domain : (- \infty, - 3) \cup (4, \infty)

Range : (- \infty, \infty)

Solution steps

Domain of

lo g_{\frac{1}{5}} (x^{2} - x - 12) + 6 : x < - 3 or x > 4

Range of

lo g_{\frac{1}{5}} (x^{2} - x - 12) + 6 : - \infty < f (x) < \infty

Axis interception points of

lo g_{\frac{1}{5}} (x^{2} - x - 12) + 6 :

X Intercepts

: (\frac{1 + 62549}{2}, 0), (\frac{1 - 62549}{2}, 0)

Extreme Points of

lo g_{\frac{1}{5}} (x^{2} - x - 12) + 6 :

None

Popular Examples

f(x)=(5-2x)/(4x-2)

f (x) = \frac{5 - 2 x}{4 x - 2}

f(x)=(sqrt(x+3)-3)/(6-x)

f (x) = \frac{x + 3 - 3}{6 - x}

f(x)=x^3-9x^2+24x-2

f (x) = x^{3} - 9 x^{2} + 24 x - 2

f(x)=sqrt(x^2-6x+8)

f (x) = x^{2} - 6 x + 8

f(x)=\sqrt[3]{x^2-6x+6}

Frequently Asked Questions (FAQ)

What is the f(x)=log_{1/5}(x^2-x-12)+6 ?
The f(x)=log_{1/5}(x^2-x-12)+6 is