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Popular >

f(x)=2x^2-8x+16

Solution

f (x) = 2 x^{2} - 8 x + 16

Solution

Domain : - \infty < x < \infty

Range : f (x) \geq 8

Y Intercepts : (0, 16)

Vertex : Minimum (2, 8)

Inverse : \frac{8 + 8 x - 64}{4}, \frac{8 - 8 x - 64}{4}

+1

Interval Notation

Domain : (- \infty, \infty)

Range : [8, \infty)

Solution steps

Domain of

2 x^{2} - 8 x + 16 : - \infty < x < \infty

Range of

2 x^{2} - 8 x + 16 : f (x) \geq 8

Axis interception points of

2 x^{2} - 8 x + 16 :

Y Intercepts

: (0, 16)

Vertex of

2 x^{2} - 8 x + 16 :

Minimum

(2, 8)

Inverse of

2 x^{2} - 8 x + 16 : \frac{8 + 8 x - 64}{4}, \frac{8 - 8 x - 64}{4}

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Frequently Asked Questions (FAQ)

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