What is the d/(dt)(1-cos(3.14*t)) ?

The d/(dt)(1-cos(3.14*t)) is 3.14sin(3.14t)

What is the first d/(dt)(1-cos(3.14*t)) ?

The first d/(dt)(1-cos(3.14*t)) is 3.14sin(3.14t)

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\frac{d}{d t} (1 - cos (3.14 \cdot t))

3.14 sin (3.14 t)

Solution steps

\frac{d}{d t} (1 - cos (3.14 t))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (1) - \frac{d}{d t} (cos (3.14 t))

\frac{d}{d t} (1) = 0

\frac{d}{d t} (cos (3.14 t)) = - sin (3.14 t) \cdot 3.14

= 0 - (- sin (3.14 t) \cdot 3.14)

Simplify

= 3.14 sin (3.14 t)

y = - x^{2} + 36

f (x) = \frac{( x + 2 ) ( x + 1 ) ^{3}}{( x + 2 ) ( x - 3 ) ^{2}}

f (x) = \frac{5 - x}{2 x + 6}

f (x) = 2 x - 3 + 5

f (θ) = sin (5 θ)

What is the d/(dt)(1-cos(3.14*t)) ?
The d/(dt)(1-cos(3.14*t)) is 3.14sin(3.14t)
What is the first d/(dt)(1-cos(3.14*t)) ?
The first d/(dt)(1-cos(3.14*t)) is 3.14sin(3.14t)