What is the domain of f(x)=sqrt((x+1)/(x^2-4x+3)) ?

The domain of f(x)=sqrt((x+1)/(x^2-4x+3)) is -1 3

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domain of f(x)=sqrt((x+1)/(x^2-4x+3))

domain

f (x) = \frac{x + 1}{x ^{2} - 4 x + 3}

- 1 \leq x < 1 or x > 3

Interval Notation

[- 1, 1) \cup (3, \infty)

Solution steps

Find non-negative values for radicals:

- 1 \leq x < 1 or x > 3

Find undefined (singularity) points:

x = 3, x = 1

Combine real regions and undefined points for final function domain

- 1 \leq x < 1 or x > 3

f (x) = 1 + x^{2}

y = \frac{10 x + 1}{x + 1}

5^{x} + 3

f (x) = x^{\frac{1}{5}}

(3, - 5), (5, 4)

What is the domain of f(x)=sqrt((x+1)/(x^2-4x+3)) ?
The domain of f(x)=sqrt((x+1)/(x^2-4x+3)) is -1<= x<1\lor x>3