What is the f(x)=tan(x/(1+x)) ?

The f(x)=tan(x/(1+x)) is Parity: Neither even nor odd Inverse: (arctan(x))/(1-arctan(x))

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f(x)=tan(x/(1+x))

f (x) = tan (\frac{x}{1 + x})

Parity : Neither even nor odd

Inverse : \frac{arctan ( x )}{1 - arctan ( x )}

Solution steps

Parity of

tan (\frac{x}{1 + x}) :

Neither even nor odd

Inverse of

tan (\frac{x}{1 + x}) : \frac{arctan ( x )}{1 - arctan ( x )}

f (x) = \frac{( x ^{2} + 3 )}{x + 3}

f (x) = x^{3} - 2 x^{2} + x - 1

y = \frac{x ln ( x )}{ln ( x ) - 2}

What is the f(x)=tan(x/(1+x)) ?
The f(x)=tan(x/(1+x)) is Parity: Neither even nor odd<br/>Inverse: (arctan(x))/(1-arctan(x))