What is the f(x)=(x-3)/2 ,0<= x<= 5 ?

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f(x)=(x-3)/2 ,0<= x<= 5

f (x) = \frac{x - 3}{2}, 0 \leq x \leq 5

X Intercepts : (3, 0), Y Intercepts : (0, - \frac{3}{2})

Slope : m = \frac{1}{2}

Inverse : 2 x + 3

Domain : 0 \leq x \leq 5

Range : - \frac{3}{2} \leq f (x) \leq 1

Interval Notation

Domain : [0, 5]

Range : [- \frac{3}{2}, 1]

Solution steps

Axis interception points of

\frac{x - 3}{2}, 0 \leq x \leq 5 :

X Intercepts

: (3, 0),

Y Intercepts

: (0, - \frac{3}{2})

Slope of

\frac{x - 3}{2} : m = \frac{1}{2}

Inverse of

\frac{x - 3}{2}, 0 \leq x \leq 5 : 2 x + 3

Domain of

\frac{x - 3}{2}, 0 \leq x \leq 5 : 0 \leq x \leq 5

Range of

\frac{x - 3}{2}, 0 \leq x \leq 5 : - \frac{3}{2} \leq f (x) \leq 1

f (x) = \frac{1}{3 x ^{3} - ln ∣ x ∣ + e ^{2}}

y = \frac{x ^{2} + x}{x + 1}

f (x) = 3 x^{\frac{5}{3}} - 2 x^{\frac{2}{3}}

g (x) = \frac{x + 3}{x + 2}

z, w = 3 z^{- 2} - \frac{1}{z}