en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

midpoint (a,2b),(2a,b-2)

Solution

midpoint

(a, 2 b), (2 a, b - 2)

Solution

(\frac{3 a}{2}, \frac{3 b - 2}{2})

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (a, 2 b), (x_{2}, y_{2}) = (2 a, b - 2)

= (\frac{2 a + a}{2}, \frac{b - 2 + 2 b}{2})

Refine

= (\frac{3 a}{2}, \frac{3 b - 2}{2})

Popular Examples

inverse of-ln(x+3)+e inverse

- ln (x + 3) + e

asymptotes of f(x)=(x-1)/(x^2-4x+3)asymptotes

f (x) = \frac{x - 1}{x ^{2} - 4 x + 3}

domain of f(x)=(8-x)(3x+2)domain

f (x) = (8 - x) (3 x + 2)

parallel y=4x+7 parallel

y = 4 x + 7

domain of f(x)=(4x)/(x-1)domain

f (x) = \frac{4 x}{x - 1}

Frequently Asked Questions (FAQ)

What is the midpoint (a,2b),(2a,b-2) ?
The midpoint (a,2b),(2a,b-2) is ((3a)/2 ,(3b-2)/2)