What is the f(x)=(\sqrt[3]{x})/(\sqrt[3]{x)-1} ?

The f(x)=(\sqrt[3]{x})/(\sqrt[3]{x)-1} is

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f(x)=(\sqrt[3]{x})/(\sqrt[3]{x)-1}

Domain : x < 1 or x > 1

Range : f (x) < 1 or f (x) > 1

X Intercepts : (0, 0), Y Intercepts : (0, 0)

Asymptotes : Vertical x = 1, Horizontal y = 1

Extreme Points : None

Interval Notation

Domain : (- \infty, 1) \cup (1, \infty)

Range : (- \infty, 1) \cup (1, \infty)

Solution steps

Domain of

Range of

Axis interception points of

X Intercepts

: (0, 0),

Y Intercepts

: (0, 0)

Asymptotes of

Vertical

: x = 1,

Horizontal

: y = 1

Extreme Points of

None

f (x) = x^{3} - 6 x^{2} + 4 x - 24

f (x) = 4 t^{2} - 6

f (x) = 4 x^{2} + 40 x + 93

f (x) = \frac{x - 1}{x ^{2} - 4}

h (x) = x - 10

What is the f(x)=(\sqrt[3]{x})/(\sqrt[3]{x)-1} ?
The f(x)=(\sqrt[3]{x})/(\sqrt[3]{x)-1} is