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Popular >

p(x)=x^6-x^4+2x^2-1

Solution

p (x) = x^{6} - x^{4} + 2 x^{2} - 1

Solution

Domain : - \infty < x < \infty

Range : f (x) \geq - 1

X Intercepts : (\frac{1.4246 E 15}{2.5 E 15}, 0), (- \frac{1.4246 E 15}{2.5 E 15}, 0), Y Intercepts : (0, - 1)

Asymptotes : None

Extreme Points : Minimum (0, - 1)

+1

Interval Notation

Domain : (- \infty, \infty)

Range : [- 1, \infty)

Solution steps

Domain of

x^{6} - x^{4} + 2 x^{2} - 1 : - \infty < x < \infty

Range of

x^{6} - x^{4} + 2 x^{2} - 1 : f (x) \geq - 1

Axis interception points of

x^{6} - x^{4} + 2 x^{2} - 1 :

X Intercepts

: (\frac{1.4246 E 15}{2.5 E 15}, 0), (- \frac{1.4246 E 15}{2.5 E 15}, 0),

Y Intercepts

: (0, - 1)

Asymptotes of

x^{6} - x^{4} + 2 x^{2} - 1 :

None

Extreme Points of

x^{6} - x^{4} + 2 x^{2} - 1 :

Minimum

(0, - 1)

Popular Examples

y=(x+2)/(x^2-4)

y = \frac{x + 2}{x ^{2} - 4}

f(x)=(sqrt(x+4))/(x-4)

f (x) = \frac{x + 4}{x - 4}

g(x)=(x-1)/(e^{x^2+1)}

g (x) = \frac{x - 1}{e ^{x^{2} + 1}}

f(x)=log_{10}(2/5)x

f (x) = lo g_{10} (\frac{2}{5}) x

y=sec^2(x)-tan^2(x)

y = sec^{2} (x) - tan^{2} (x)

Frequently Asked Questions (FAQ)

What is the p(x)=x^6-x^4+2x^2-1 ?
The p(x)=x^6-x^4+2x^2-1 is