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Popular >

p(t)=10(1.05)^t

Solution

p (t) = 10 (1.05)^{t}

Solution

Domain : - \infty < t < \infty

Range : f (t) > 0

Y Intercepts : (0, 10)

Asymptotes : Horizontal y = 0

Extreme Points : None

+1

Interval Notation

Domain : (- \infty, \infty)

Range : (0, \infty)

Solution steps

Domain of

101.0 5^{t} : - \infty < t < \infty

Range of

101.0 5^{t} : f (t) > 0

Axis interception points of

101.0 5^{t} :

Y Intercepts

: (0, 10)

Asymptotes of

101.0 5^{t} :

Horizontal

: y = 0

Extreme Points of

101.0 5^{t} :

None

Popular Examples

f(t)=t^2+2t^4+1

f (t) = t^{2} + 2 t^{4} + 1

f(x)=5x^2sqrt(x+1)

f (x) = 5 x^{2} x + 1

y = - 2 x^{2} - 5

y=-x^3-5x^2-3x+9

y = - x^{3} - 5 x^{2} - 3 x + 9

f(x)=(3x-6)/(x+2)

f (x) = \frac{3 x - 6}{x + 2}

Frequently Asked Questions (FAQ)

What is the p(t)=10(1.05)^t ?
The p(t)=10(1.05)^t is