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Popular >

y=sqrt(x^2+x-1)

Solution

y = x^{2} + x - 1

Solution

Domain : x \leq \frac{- 5 - 1}{2} or x \geq \frac{5 - 1}{2}

Range : f (x) \geq 0

X Intercepts : (\frac{- 1 + 5}{2}, 0), (\frac{- 1 - 5}{2}, 0)

Asymptotes : None

Extreme Points : Minimum (\frac{- 1 - 5}{2}, 0), Minimum (\frac{- 1 + 5}{2}, 0)

+1

Interval Notation

Domain : (- \infty, \frac{- 5 - 1}{2}] \cup [\frac{5 - 1}{2}, \infty)

Range : [0, \infty)

Solution steps

Domain of

x^{2} + x - 1 : x \leq \frac{- 5 - 1}{2} or x \geq \frac{5 - 1}{2}

Range of

x^{2} + x - 1 : f (x) \geq 0

Axis interception points of

x^{2} + x - 1 :

X Intercepts

: (\frac{- 1 + 5}{2}, 0), (\frac{- 1 - 5}{2}, 0)

Asymptotes of

x^{2} + x - 1 :

None

Extreme Points of

x^{2} + x - 1 :

Minimum

(\frac{- 1 - 5}{2}, 0),

Minimum

(\frac{- 1 + 5}{2}, 0)

Popular Examples

f(x)=-0.5x^2+7x-3

f (x) = - 0.5 x^{2} + 7 x - 3

y = 1 + \frac{1}{x}

f(x)=(x+1)*(x^2)

f (x) = (x + 1) \cdot (x^{2})

f(x)=sqrt(1-e^{2x)}

f (x) = 1 - e^{2 x}

g(x)=log_{10}(x-4)

g (x) = lo g_{10} (x - 4)

Frequently Asked Questions (FAQ)

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