What is the domain of (x+1)/(2x-2)-(x-1)/(2x+2)-2/(1-x^2) ?

The domain of (x+1)/(2x-2)-(x-1)/(2x+2)-2/(1-x^2) is x 1

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domain of (x+1)/(2x-2)-(x-1)/(2x+2)-2/(1-x^2)

domain

\frac{x + 1}{2 x - 2} - \frac{x - 1}{2 x + 2} - \frac{2}{1 - x ^{2}}

x < - 1 or - 1 < x < 1 or x > 1

Interval Notation

(- \infty, - 1) \cup (- 1, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1, x = - 1

The function domain

x < - 1 or - 1 < x < 1 or x > 1

- 2 x

y = x + 4

\frac{x ^{2} - 16}{2 x ^{2} - 13 x + 20}

x - 3 y = - 9

(\frac{2}{3})^{x}

What is the domain of (x+1)/(2x-2)-(x-1)/(2x+2)-2/(1-x^2) ?
The domain of (x+1)/(2x-2)-(x-1)/(2x+2)-2/(1-x^2) is x<-1\lor-1<x<1\lor x>1