What is the f(x)=((x^4-13x^2+36)x)/(x^3+2x^2-9x-18) ?

The f(x)=((x^4-13x^2+36)x)/(x^3+2x^2-9x-18) is

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f(x)=((x^4-13x^2+36)x)/(x^3+2x^2-9x-18)

f (x) = \frac{( x ^{4} - 13 x ^{2} + 36 ) x}{x ^{3} + 2 x ^{2} - 9 x - 18}

Domain : x < - 3 or - 3 < x < - 2 or - 2 < x < 3 or x > 3

Range : f (x) \geq - 1

X Intercepts : (0, 0), (2, 0), Y Intercepts : (0, 0)

Asymptotes : None

Extreme Points : Minimum (1, - 1)

Interval Notation

Domain : (- \infty, - 3) \cup (- 3, - 2) \cup (- 2, 3) \cup (3, \infty)

Range : [- 1, \infty)

Solution steps

Domain of

\frac{( x ^{4} - 13 x ^{2} + 36 ) x}{x ^{3} + 2 x ^{2} - 9 x - 18} : x < - 3 or - 3 < x < - 2 or - 2 < x < 3 or x > 3

Range of

\frac{( x ^{4} - 13 x ^{2} + 36 ) x}{x ^{3} + 2 x ^{2} - 9 x - 18} : f (x) \geq - 1

Axis interception points of

\frac{( x ^{4} - 13 x ^{2} + 36 ) x}{x ^{3} + 2 x ^{2} - 9 x - 18} :

X Intercepts

: (0, 0), (2, 0),

Y Intercepts

: (0, 0)

Asymptotes of

\frac{( x ^{4} - 13 x ^{2} + 36 ) x}{x ^{3} + 2 x ^{2} - 9 x - 18} :

None

Extreme Points of

\frac{( x ^{4} - 13 x ^{2} + 36 ) x}{x ^{3} + 2 x ^{2} - 9 x - 18} :

Minimum

(1, - 1)

f (x) = 8 x - 3 x

y = 1 - x

y = \frac{x + 1}{x ^{2} - 4}

f (x) = 0.5 x^{2} - 4 x + 6

f (x) = \frac{x + 7}{x ^{2} - 14 x + 49}

What is the f(x)=((x^4-13x^2+36)x)/(x^3+2x^2-9x-18) ?
The f(x)=((x^4-13x^2+36)x)/(x^3+2x^2-9x-18) is