What is the d/(dt)(4cos(t)) ?

The d/(dt)(4cos(t)) is -4sin(t)

What is the first d/(dt)(4cos(t)) ?

The first d/(dt)(4cos(t)) is -4sin(t)

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\frac{d}{d t} (4 cos (t))

- 4 sin (t)

Solution steps

\frac{d}{d t} (4 cos (t))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d t} (cos (t))

Apply the common derivative:

\frac{d}{d t} (cos (t)) = - sin (t)

= 4 (- sin (t))

Simplify

= - 4 sin (t)

f (x) = \frac{1}{0}

f (x) = \frac{x - ∣ x ∣}{4}

p (x) = 2 x^{3} + \frac{2}{3} x^{2} - 5 x + \frac{1}{2}

y = \frac{- 6 sin ( 2 x ^{3} )}{4 x ^{2}}

f (x) = 2 x - 1