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Popular >

f(t)=(10t)/(t^2+1)

Solution

f (t) = \frac{10 t}{t ^{2} + 1}

Solution

Domain : - \infty < t < \infty

Range : - 5 \leq f (t) \leq 5

X Intercepts : (0, 0), Y Intercepts : (0, 0)

Asymptotes : Horizontal y = 0

Extreme Points : Minimum (- 1, - 5), Maximum (1, 5)

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Interval Notation

Domain : (- \infty, \infty)

Range : [- 5, 5]

Solution steps

Domain of

\frac{10 t}{t ^{2} + 1} : - \infty < t < \infty

Range of

\frac{10 t}{t ^{2} + 1} : - 5 \leq f (t) \leq 5

Axis interception points of

\frac{10 t}{t ^{2} + 1} :

X Intercepts

: (0, 0),

Y Intercepts

: (0, 0)

Asymptotes of

\frac{10 t}{t ^{2} + 1} :

Horizontal

: y = 0

Extreme Points of

\frac{10 t}{t ^{2} + 1} :

Minimum

(- 1, - 5),

Maximum

(1, 5)

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f (x) = - x^{2} - 5 x - 2

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Frequently Asked Questions (FAQ)

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