What is the asymptotes of f(x)=(2x^2+4x+2)/(x^2-1) ?

The asymptotes of f(x)=(2x^2+4x+2)/(x^2-1) is Vertical: x=1,Horizontal: y=2

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asymptotes of f(x)=(2x^2+4x+2)/(x^2-1)

asymptotes

f (x) = \frac{2 x ^{2} + 4 x + 2}{x ^{2} - 1}

Vertical : x = 1, Horizontal : y = 2

Solution steps

Vertical asymptotes of

\frac{2 x ^{2} + 4 x + 2}{x ^{2} - 1} : x = 1

Horizontal Asymptotes of

\frac{2 x ^{2} + 4 x + 2}{x ^{2} - 1} : y = 2

Slant Asymptotes of

\frac{2 x ^{2} + 4 x + 2}{x ^{2} - 1} :

None

Vertical : x = 1, Horizontal : y = 2

f (x) = - x - 3 + 2

y = \frac{5}{2} x, (2, 5)

f (x) = x x

f (x) = x^{4} - 8 x^{2} + 1

f (x) = - 4 x^{2} + 3

What is the asymptotes of f(x)=(2x^2+4x+2)/(x^2-1) ?
The asymptotes of f(x)=(2x^2+4x+2)/(x^2-1) is Vertical: x=1,Horizontal: y=2