What is the f(x)=(1-9x^2)/(6x^3-x|9-2x|-3) ?

The f(x)=(1-9x^2)/(6x^3-x|9-2x|-3) is

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f(x)=(1-9x^2)/(6x^3-x|9-2x|-3)

f (x) = \frac{1 - 9 x ^{2}}{6 x ^{3} - x ∣ 9 - 2 x ∣ - 3}

Domain : x < - \frac{3}{2} or - \frac{3}{2} < x < - \frac{1}{3} or - \frac{1}{3} < x < \frac{3}{2} or x > \frac{3}{2}

X Intercepts : (\frac{1}{3}, 0), Y Intercepts : (0, - \frac{1}{3})

Asymptotes : Vertical x = - \frac{3}{2}, x = \frac{3}{2}, Horizontal y = 0

Extreme Points : None

Interval Notation

Domain : (- \infty, - \frac{3}{2}) \cup (- \frac{3}{2}, - \frac{1}{3}) \cup (- \frac{1}{3}, \frac{3}{2}) \cup (\frac{3}{2}, \infty)

Solution steps

Domain of

\frac{1 - 9 x ^{2}}{6 x ^{3} - x ∣ 9 - 2 x ∣ - 3} : x < - \frac{3}{2} or - \frac{3}{2} < x < - \frac{1}{3} or - \frac{1}{3} < x < \frac{3}{2} or x > \frac{3}{2}

Axis interception points of

\frac{1 - 9 x ^{2}}{6 x ^{3} - x ∣ 9 - 2 x ∣ - 3} :

X Intercepts

: (\frac{1}{3}, 0),

Y Intercepts

: (0, - \frac{1}{3})

Asymptotes of

\frac{1 - 9 x ^{2}}{6 x ^{3} - x ∣ 9 - 2 x ∣ - 3} :

Vertical

: x = - \frac{3}{2}, x = \frac{3}{2},

Horizontal

: y = 0

Extreme Points of

\frac{1 - 9 x ^{2}}{6 x ^{3} - x ∣ 9 - 2 x ∣ - 3} :

None

f (s) = \frac{3 s}{s ^{2} - 12 + 30}

y = e^{x} + 3

y = \frac{1}{x - 2} + 1

f (x) = \frac{x ^{2} + 1}{x ^{2} - 9}

f (x) = x^{2} - 9 x + 6

What is the f(x)=(1-9x^2)/(6x^3-x|9-2x|-3) ?
The f(x)=(1-9x^2)/(6x^3-x|9-2x|-3) is