What is the f(x)=(sqrt(4-x^2))/(x^2-4x+3) ?

The f(x)=(sqrt(4-x^2))/(x^2-4x+3) is

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f(x)=(sqrt(4-x^2))/(x^2-4x+3)

f (x) = \frac{4 - x ^{2}}{x ^{2} - 4 x + 3}

Domain : - 2 \leq x < 1 or 1 < x \leq 2

Range : - \infty < f (x) < \infty

X Intercepts : (2, 0), (- 2, 0), Y Intercepts : (0, \frac{2}{3})

Asymptotes : Vertical x = 1

Extreme Points : Minimum (- 2, 0), Maximum (2, 0)

Interval Notation

Domain : [- 2, 1) \cup (1, 2]

Range : (- \infty, \infty)

Solution steps

Domain of

\frac{4 - x ^{2}}{x ^{2} - 4 x + 3} : - 2 \leq x < 1 or 1 < x \leq 2

Range of

\frac{4 - x ^{2}}{x ^{2} - 4 x + 3} : - \infty < f (x) < \infty

Axis interception points of

\frac{4 - x ^{2}}{x ^{2} - 4 x + 3} :

X Intercepts

: (2, 0), (- 2, 0),

Y Intercepts

: (0, \frac{2}{3})

Asymptotes of

\frac{4 - x ^{2}}{x ^{2} - 4 x + 3} :

Vertical

: x = 1

Extreme Points of

\frac{4 - x ^{2}}{x ^{2} - 4 x + 3} :

Minimum

(- 2, 0),

Maximum

(2, 0)

r, r = \frac{1}{3} tan (θ) sec (θ)

f (- 3) = - 2 x^{2} - 5 x

f (x) = lo g_{4} (x + 2) + 1

g (x) = \frac{x ^{2} + 1}{x ^{2} - 1}

f (x) = x + 2 - x

What is the f(x)=(sqrt(4-x^2))/(x^2-4x+3) ?
The f(x)=(sqrt(4-x^2))/(x^2-4x+3) is