What is the f(x)=(3x^4-2x^3+16x-192)/(x^2-8) ?

The f(x)=(3x^4-2x^3+16x-192)/(x^2-8) is

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f(x)=(3x^4-2x^3+16x-192)/(x^2-8)

f (x) = \frac{3 x ^{4} - 2 x ^{3} + 16 x - 192}{x ^{2} - 8}

Domain : x < - 22 or - 22 < x < 22 or x > 22

Range : f (x) \geq \frac{71}{3}

Y Intercepts : (0, 24)

Asymptotes : None

Extreme Points : Minimum (\frac{1}{3}, \frac{71}{3})

Interval Notation

Domain : (- \infty, - 22) \cup (- 22, 22) \cup (22, \infty)

Range : [\frac{71}{3}, \infty)

Solution steps

Domain of

\frac{3 x ^{4} - 2 x ^{3} + 16 x - 192}{x ^{2} - 8} : x < - 22 or - 22 < x < 22 or x > 22

Range of

\frac{3 x ^{4} - 2 x ^{3} + 16 x - 192}{x ^{2} - 8} : f (x) \geq \frac{71}{3}

Axis interception points of

\frac{3 x ^{4} - 2 x ^{3} + 16 x - 192}{x ^{2} - 8} :

Y Intercepts

: (0, 24)

Asymptotes of

\frac{3 x ^{4} - 2 x ^{3} + 16 x - 192}{x ^{2} - 8} :

None

Extreme Points of

\frac{3 x ^{4} - 2 x ^{3} + 16 x - 192}{x ^{2} - 8} :

Minimum

(\frac{1}{3}, \frac{71}{3})

f (x) = x (x^{3} - x + 10)

f (x) = \frac{x - 1}{( x + 3 ) ( 2 x - 5 )}

f (x) = ln (cos^{5} (3 x^{4}))

g (x) = x^{2} + 6

f (x) = \frac{1}{x - 5} + 1

What is the f(x)=(3x^4-2x^3+16x-192)/(x^2-8) ?
The f(x)=(3x^4-2x^3+16x-192)/(x^2-8) is