What is the f(x)=(3(3-x)(x+1))/((x-1)(x-2)) ?

The f(x)=(3(3-x)(x+1))/((x-1)(x-2)) is

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f(x)=(3(3-x)(x+1))/((x-1)(x-2))

f (x) = \frac{3 ( 3 - x ) ( x + 1 )}{( x - 1 ) ( x - 2 )}

Domain : x < 1 or 1 < x < 2 or x > 2

Range : f (x) \leq - 123 - 24 or f (x) \geq 123 - 24

X Intercepts : (3, 0), (- 1, 0), Y Intercepts : (0, \frac{9}{2})

Asymptotes : Vertical x = 1, x = 2, Horizontal y = - 3

Extreme Points : Maximum (5 - 23, - 12 (2 + 3)), Minimum (5 + 23, - 12 (2 - 3))

Interval Notation

Domain : (- \infty, 1) \cup (1, 2) \cup (2, \infty)

Range : (- \infty, - 123 - 24] \cup [123 - 24, \infty)

Solution steps

Domain of

\frac{3 ( 3 - x ) ( x + 1 )}{( x - 1 ) ( x - 2 )} : x < 1 or 1 < x < 2 or x > 2

Range of

\frac{3 ( 3 - x ) ( x + 1 )}{( x - 1 ) ( x - 2 )} : f (x) \leq - 123 - 24 or f (x) \geq 123 - 24

Axis interception points of

\frac{3 ( 3 - x ) ( x + 1 )}{( x - 1 ) ( x - 2 )} :

X Intercepts

: (3, 0), (- 1, 0),

Y Intercepts

: (0, \frac{9}{2})

Asymptotes of

\frac{3 ( 3 - x ) ( x + 1 )}{( x - 1 ) ( x - 2 )} :

Vertical

: x = 1, x = 2,

Horizontal

: y = - 3

Extreme Points of

\frac{3 ( 3 - x ) ( x + 1 )}{( x - 1 ) ( x - 2 )} :

Maximum

(5 - 23, - 12 (2 + 3)),

Minimum

(5 + 23, - 12 (2 - 3))

f (x) = \frac{6 x + 4}{2 x - 1}

f (x) = 3 (3)^{x - 1}

y = 3 - x^{2}

f (x) = ∣ x - 5 ∣ + 1

f (x) = lo g_{2} (x^{2} - 4)

What is the f(x)=(3(3-x)(x+1))/((x-1)(x-2)) ?
The f(x)=(3(3-x)(x+1))/((x-1)(x-2)) is