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Popular >

y=-1/2 (2x+1)(2x-5)

Solution

y = - \frac{1}{2} (2 x + 1) (2 x - 5)

Solution

Domain : - \infty < x < \infty

Range : f (x) \leq \frac{9}{2}

X Intercepts : (- \frac{1}{2}, 0), (\frac{5}{2}, 0), Y Intercepts : (0, \frac{5}{2})

Vertex : Maximum (1, \frac{9}{2})

Inverse : - \frac{- 2 + - 2 x + 9}{2}, \frac{- 2 x + 9 + 2}{2}

+1

Interval Notation

Domain : (- \infty, \infty)

Range : (- \infty, \frac{9}{2}]

Solution steps

Domain of

- \frac{1}{2} (2 x + 1) (2 x - 5) : - \infty < x < \infty

Range of

- \frac{1}{2} (2 x + 1) (2 x - 5) : f (x) \leq \frac{9}{2}

Axis interception points of

- \frac{1}{2} (2 x + 1) (2 x - 5) :

X Intercepts

: (- \frac{1}{2}, 0), (\frac{5}{2}, 0),

Y Intercepts

: (0, \frac{5}{2})

Vertex of

- \frac{1}{2} (2 x + 1) (2 x - 5) :

Maximum

(1, \frac{9}{2})

Inverse of

- \frac{1}{2} (2 x + 1) (2 x - 5) : - \frac{- 2 + - 2 x + 9}{2}, \frac{- 2 x + 9 + 2}{2}

Popular Examples

f (x) = (x + 3)^{2} - 7

f(x)=(2-5x)/(2+2x)

f (x) = \frac{2 - 5 x}{2 + 2 x}

f(t)=t^4-12t^3+48t^2-64t

f (t) = t^{4} - 12 t^{3} + 48 t^{2} - 64 t

f(x)=0.002x^3-0.05x^2+0.1x-11

f (x) = 0.002 x^{3} - 0.05 x^{2} + 0.1 x - 11

f(x)=sqrt(x^2+5x+4)

f (x) = x^{2} + 5 x + 4

Frequently Asked Questions (FAQ)

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