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Popular >

f(x)=(2x^2+2)/(x^2-4)

Solution

f (x) = \frac{2 x ^{2} + 2}{x ^{2} - 4}

Solution

Domain : x < - 2 or - 2 < x < 2 or x > 2

Range : f (x) \leq - \frac{1}{2} or f (x) > 2

Y Intercepts : (0, - \frac{1}{2})

Asymptotes : Vertical x = - 2, x = 2, Horizontal y = 2

Extreme Points : Maximum (0, - \frac{1}{2})

+1

Interval Notation

Domain : (- \infty, - 2) \cup (- 2, 2) \cup (2, \infty)

Range : (- \infty, - \frac{1}{2}] \cup (2, \infty)

Solution steps

Domain of

\frac{2 x ^{2} + 2}{x ^{2} - 4} : x < - 2 or - 2 < x < 2 or x > 2

Range of

\frac{2 x ^{2} + 2}{x ^{2} - 4} : f (x) \leq - \frac{1}{2} or f (x) > 2

Axis interception points of

\frac{2 x ^{2} + 2}{x ^{2} - 4} :

Y Intercepts

: (0, - \frac{1}{2})

Asymptotes of

\frac{2 x ^{2} + 2}{x ^{2} - 4} :

Vertical

: x = - 2, x = 2,

Horizontal

: y = 2

Extreme Points of

\frac{2 x ^{2} + 2}{x ^{2} - 4} :

Maximum

(0, - \frac{1}{2})

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C(x)=6820+(81-x^2)/(9-x)

C (x) = 6820 + \frac{81 - x ^{2}}{9 - x}

f (x) = \frac{2 x - 4}{3}

Frequently Asked Questions (FAQ)

What is the f(x)=(2x^2+2)/(x^2-4) ?
The f(x)=(2x^2+2)/(x^2-4) is