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Popular >

f(p)=(60p)/(0.0001p^2+100)

Solution

f (p) = \frac{60 p}{0.0001 p ^{2} + 100}

Solution

Domain : - \infty < p < \infty

Range : - 300 \leq f (x) \leq 300

X Intercepts : (0, 0), Y Intercepts : (0, 0)

Asymptotes : Horizontal y = \frac{60 p}{0.0001 p ^{2} + 100}

Extreme Points : Minimum (- 1000, - 300), Maximum (1000, 300)

+1

Interval Notation

Domain : (- \infty, \infty)

Range : [- 300, 300]

Solution steps

Domain of

\frac{60 p}{0.0001 p ^{2} + 100} : - \infty < p < \infty

Range of

\frac{60 p}{0.0001 p ^{2} + 100} : - 300 \leq f (x) \leq 300

Axis interception points of

\frac{60 p}{0.0001 p ^{2} + 100} :

X Intercepts

: (0, 0),

Y Intercepts

: (0, 0)

Asymptotes of

\frac{60 p}{0.0001 p ^{2} + 100} :

Horizontal

: y = \frac{60 p}{0.0001 p ^{2} + 100}

Extreme Points of

\frac{60 p}{0.0001 p ^{2} + 100} :

Minimum

(- 1000, - 300),

Maximum

(1000, 300)

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Frequently Asked Questions (FAQ)

What is the f(p)=(60p)/(0.0001p^2+100) ?
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