What is the f(x)=(-2(x-3)(x+1))/((x+1)(x-2)) ?

The f(x)=(-2(x-3)(x+1))/((x+1)(x-2)) is

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f(x)=(-2(x-3)(x+1))/((x+1)(x-2))

f (x) = \frac{- 2 ( x - 3 ) ( x + 1 )}{( x + 1 ) ( x - 2 )}

Domain : x < - 1 or - 1 < x < 2 or x > 2

Range : f (x) > - \frac{8}{3}

X Intercepts : (3, 0), Y Intercepts : (0, - 3)

Asymptotes : Vertical x = 2, Horizontal y = - 2

Extreme Points : None

Interval Notation

Domain : (- \infty, - 1) \cup (- 1, 2) \cup (2, \infty)

Range : (- \frac{8}{3}, \infty)

Solution steps

Domain of

\frac{- 2 ( x - 3 ) ( x + 1 )}{( x + 1 ) ( x - 2 )} : x < - 1 or - 1 < x < 2 or x > 2

Range of

\frac{- 2 ( x - 3 ) ( x + 1 )}{( x + 1 ) ( x - 2 )} : f (x) > - \frac{8}{3}

Axis interception points of

\frac{- 2 ( x - 3 ) ( x + 1 )}{( x + 1 ) ( x - 2 )} :

X Intercepts

: (3, 0),

Y Intercepts

: (0, - 3)

Asymptotes of

\frac{- 2 ( x - 3 ) ( x + 1 )}{( x + 1 ) ( x - 2 )} :

Vertical

: x = 2,

Horizontal

: y = - 2

Extreme Points of

\frac{- 2 ( x - 3 ) ( x + 1 )}{( x + 1 ) ( x - 2 )} :

None

y = x^{2} - 4 x - 9

f (x) = - \frac{2}{x ^{3}} + \frac{3}{x ^{2}} - 4 x

f (x) = - \frac{1}{x - 4}

y = \frac{- 2}{( s + 3 )} + \frac{5}{( s + 1 )}

f (x) = - 2 x^{2} - 3 x

What is the f(x)=(-2(x-3)(x+1))/((x+1)(x-2)) ?
The f(x)=(-2(x-3)(x+1))/((x+1)(x-2)) is