What is the inverse of f(x)=sin^2(x) ?

The inverse of f(x)=sin^2(x) is arcsin(sqrt(x)),arcsin(-sqrt(x))

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inverse of f(x)=sin^2(x)

inverse

f (x) = sin^{2} (x)

arcsin (x), arcsin (- x)

Solution steps

Solve for

sin (x), y = sin^{2} (x)

sin (x) = y, sin (x) = - y

sin (a) = b \Rightarrow a = arcsin (b)

arcsin (y), arcsin (- y)

Substitute

y = x

arcsin (x), arcsin (- x)

f (x) = \frac{x ^{2} - 4}{x ^{4} - 81}

f (x) = - 2

(- 3.4) (1.2)

\frac{8}{t ^{2} - 81}

x^{3} - 9 x^{2} + 27 x + 3

What is the inverse of f(x)=sin^2(x) ?
The inverse of f(x)=sin^2(x) is arcsin(sqrt(x)),arcsin(-sqrt(x))