What is the y=(x^3)/6+1/(2x), 1/2 <= x<= 1 ?

The y=(x^3)/6+1/(2x), 1/2 <= x<= 1 is

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y=(x^3)/6+1/(2x), 1/2 <= x<= 1

y = \frac{x ^{3}}{6} + \frac{1}{2 x}, \frac{1}{2} \leq x \leq 1

Domain : \frac{1}{2} \leq x \leq 1

Range : \frac{2}{3} \leq f (x) \leq \frac{49}{48}

Intercepts : None

Asymptotes : None

Extreme Points : Maximum (\frac{1}{2}, \frac{49}{48}), Minimum (1, \frac{2}{3})

Interval Notation

Domain : [\frac{1}{2}, 1]

Range : [\frac{2}{3}, \frac{49}{48}]

Solution steps

Domain of

\frac{x ^{3}}{6} + \frac{1}{2 x}, \frac{1}{2} \leq x \leq 1 : \frac{1}{2} \leq x \leq 1

Range of

\frac{x ^{3}}{6} + \frac{1}{2 x}, \frac{1}{2} \leq x \leq 1 : \frac{2}{3} \leq f (x) \leq \frac{49}{48}

Axis interception points of

\frac{x ^{3}}{6} + \frac{1}{2 x}, \frac{1}{2} \leq x \leq 1 :

None

Asymptotes of

\frac{x ^{3}}{6} + \frac{1}{2 x}, \frac{1}{2} \leq x \leq 1 :

None

Extreme Points of

\frac{x ^{3}}{6} + \frac{1}{2 x}, \frac{1}{2} \leq x \leq 1 :

Maximum

(\frac{1}{2}, \frac{49}{48}),

Minimum

(1, \frac{2}{3})

y = \frac{x ^{2}}{2} + x

f (x) = cos (3 x) cos (5 x)

f (x) = 25 + x

f (x) = \frac{1}{4} x + 5

f (x) = sin (x) + sin (2 x) + sin (3 x)

What is the y=(x^3)/6+1/(2x), 1/2 <= x<= 1 ?
The y=(x^3)/6+1/(2x), 1/2 <= x<= 1 is