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Popular >

Q(t)=50+10ln(1/(t+3))

Solution

Q (t) = 50 + 10 ln (\frac{1}{t + 3})

Solution

Domain : t > - 3

Range : - \infty < f (t) < \infty

X Intercepts : (e^{5} - 3, 0), Y Intercepts : (0, 50 - 10 ln (3))

Asymptotes : Vertical t = - 3

Extreme Points : None

+1

Interval Notation

Domain : (- 3, \infty)

Range : (- \infty, \infty)

Solution steps

Domain of

50 + 10 ln (\frac{1}{t + 3}) : t > - 3

Range of

50 + 10 ln (\frac{1}{t + 3}) : - \infty < f (t) < \infty

Axis interception points of

50 + 10 ln (\frac{1}{t + 3}) :

X Intercepts

: (e^{5} - 3, 0),

Y Intercepts

: (0, 50 - 10 ln (3))

Asymptotes of

50 + 10 ln (\frac{1}{t + 3}) :

Vertical

: t = - 3

Extreme Points of

50 + 10 ln (\frac{1}{t + 3}) :

None

Popular Examples

y = arccos (\frac{x}{2})

f(x)=log_{2/3}(x+2)-4

f (x) = lo g_{\frac{2}{3}} (x + 2) - 4

f(x)=sqrt(-x)+2.3

f (x) = - x + 2.3

f(x)=-2+3x^2+2x^3

f (x) = - 2 + 3 x^{2} + 2 x^{3}

f(x)=(x-3)/(x^2-7x+10)

f (x) = \frac{x - 3}{x ^{2} - 7 x + 10}

Frequently Asked Questions (FAQ)

What is the Q(t)=50+10ln(1/(t+3)) ?
The Q(t)=50+10ln(1/(t+3)) is