What is the domain of f(x)=(\sqrt[3]{x}-3)/(x^2+1) ?

The domain of f(x)=(\sqrt[3]{x}-3)/(x^2+1) is -infinity <x<infinity

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domain of f(x)=(\sqrt[3]{x}-3)/(x^2+1)

domain

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

y = x^{2} + 3 x + 6

f (x) = (7)^{x}

f (x) = \frac{x ^{3} + 4 x ^{2} + x - 6}{x ^{2} + 2 x - 3}

f (x) = 5 x^{2} - 15 x + 2

f (x) = 3^{x + 6}

What is the domain of f(x)=(\sqrt[3]{x}-3)/(x^2+1) ?
The domain of f(x)=(\sqrt[3]{x}-3)/(x^2+1) is -infinity <x<infinity