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Popular >

f(x)=log_{4}(2^{x+1}+8)

Solution

f (x) = lo g_{4} (2^{x + 1} + 8)

Solution

Domain : - \infty < x < \infty

Range : f (x) > \frac{3}{2}

Y Intercepts : (0, lo g_{4} (10))

Asymptotes : Horizontal y = \frac{3}{2}

Extreme Points : None

+1

Interval Notation

Domain : (- \infty, \infty)

Range : (\frac{3}{2}, \infty)

Solution steps

Domain of

lo g_{4} (2^{x + 1} + 8) : - \infty < x < \infty

Range of

lo g_{4} (2^{x + 1} + 8) : f (x) > \frac{3}{2}

Axis interception points of

lo g_{4} (2^{x + 1} + 8) :

Y Intercepts

: (0, lo g_{4} (10))

Asymptotes of

lo g_{4} (2^{x + 1} + 8) :

Horizontal

: y = \frac{3}{2}

Extreme Points of

lo g_{4} (2^{x + 1} + 8) :

None

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Frequently Asked Questions (FAQ)

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