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Popular >

f(z)=z^2-z-1

Solution

f (z) = z^{2} - z - 1

Solution

Domain : - \infty < z < \infty

Range : f (z) \geq - \frac{5}{4}

X Intercepts : (\frac{1 + 5}{2}, 0), (\frac{1 - 5}{2}, 0), Y Intercepts : (0, - 1)

Vertex : Minimum (\frac{1}{2}, - \frac{5}{4})

Inverse : \frac{1 + 4 z + 5}{2}, \frac{1 - 4 z + 5}{2}

+1

Interval Notation

Domain : (- \infty, \infty)

Range : [- \frac{5}{4}, \infty)

Solution steps

Domain of

z^{2} - z - 1 : - \infty < z < \infty

Range of

z^{2} - z - 1 : f (z) \geq - \frac{5}{4}

Axis interception points of

z^{2} - z - 1 :

X Intercepts

: (\frac{1 + 5}{2}, 0), (\frac{1 - 5}{2}, 0),

Y Intercepts

: (0, - 1)

Vertex of

z^{2} - z - 1 :

Minimum

(\frac{1}{2}, - \frac{5}{4})

Inverse of

z^{2} - z - 1 : \frac{1 + 4 z + 5}{2}, \frac{1 - 4 z + 5}{2}

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Frequently Asked Questions (FAQ)

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