What is the y=arctan((a+x)/(1-ax)) ?

The y=arctan((a+x)/(1-ax)) is Parity: Neither even nor odd Inverse: (tan(x)-a)/(1+atan(x))

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y=arctan((a+x)/(1-ax))

y = arctan (\frac{a + x}{1 - a x})

Parity : Neither even nor odd

Inverse : \frac{tan ( x ) - a}{1 + a tan ( x )}

Solution steps

Parity of

arctan (\frac{a + x}{1 - a x}) :

Neither even nor odd

Inverse of

arctan (\frac{a + x}{1 - a x}) : \frac{tan ( x ) - a}{1 + a tan ( x )}

f (x) = - 4 cos (x) + 6

f (x) = \frac{- 3}{x + 2}

f (x) = \frac{2}{- x ^{2} + 4 x + 5}

f (x) = (2 x + 1)^{3} (3 - 2 x)^{2}

f (x) = ln (1 + x^{4})

What is the y=arctan((a+x)/(1-ax)) ?
The y=arctan((a+x)/(1-ax)) is Parity: Neither even nor odd<br/>Inverse: (tan(x)-a)/(1+atan(x))