What is the f(x)= 1/(1-sin(x))+1/(1+sin(x)) ?

The f(x)= 1/(1-sin(x))+1/(1+sin(x)) is

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f(x)= 1/(1-sin(x))+1/(1+sin(x))

f (x) = \frac{1}{1 - sin ( x )} + \frac{1}{1 + sin ( x )}

Period : 2 π

Domain : 2 πn \leq x < \frac{π}{2} + 2 πn or \frac{π}{2} + 2 πn < x < \frac{3 π}{2} + 2 πn or \frac{3 π}{2} + 2 πn < x < 2 π + 2 πn

Range : f (x) \geq 2

Y Intercepts : (0, 2)

Asymptotes : Vertical x = \frac{3 π}{2} + 2 πn, x = \frac{π}{2} + 2 πn

Extreme Points : Minimum (2 πn, 2), Minimum (π + 2 πn, 2)

Interval Notation

Domain : [2 πn, \frac{π}{2} + 2 πn) \cup (\frac{π}{2} + 2 πn, \frac{3 π}{2} + 2 πn) \cup (\frac{3 π}{2} + 2 πn, 2 π + 2 πn)

Range : [2, \infty)

Solution steps

Periodicity of

\frac{1}{1 - sin ( x )} + \frac{1}{1 + sin ( x )} : 2 π

Domain of

\frac{1}{1 - sin ( x )} + \frac{1}{1 + sin ( x )} : 2 πn \leq x < \frac{π}{2} + 2 πn or \frac{π}{2} + 2 πn < x < \frac{3 π}{2} + 2 πn or \frac{3 π}{2} + 2 πn < x < 2 π + 2 πn

Range of

\frac{1}{1 - sin ( x )} + \frac{1}{1 + sin ( x )} : f (x) \geq 2

Axis interception points of

\frac{1}{1 - sin ( x )} + \frac{1}{1 + sin ( x )} :

Y Intercepts

: (0, 2)

Asymptotes of

\frac{1}{1 - sin ( x )} + \frac{1}{1 + sin ( x )} :

Vertical

: x = \frac{3 π}{2} + 2 πn, x = \frac{π}{2} + 2 πn

Extreme Points of

\frac{1}{1 - sin ( x )} + \frac{1}{1 + sin ( x )} :

Minimum

(2 πn, 2),

Minimum

(π + 2 πn, 2)

y = \frac{3}{x ^{3}} + x^{- 4}

f (x) = - 5 (4)^{x} - 10

f (x) = x (x - 3) (5 x + 2)

y = 2 \cdot 3^{- x} - 4

f (x) = \frac{3}{x - 3} + \frac{4 - x ^{2} - 1}{1 - ∣ x - 2 ∣}

What is the f(x)= 1/(1-sin(x))+1/(1+sin(x)) ?
The f(x)= 1/(1-sin(x))+1/(1+sin(x)) is