What is the f(x)=(-(x+3)(x-1))/((x-1)(x+2)) ?

The f(x)=(-(x+3)(x-1))/((x-1)(x+2)) is

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f(x)=(-(x+3)(x-1))/((x-1)(x+2))

f (x) = \frac{- ( x + 3 ) ( x - 1 )}{( x - 1 ) ( x + 2 )}

Domain : x < - 2 or - 2 < x < 1 or x > 1

Range : f (x) < - \frac{4}{3} or - \frac{4}{3} < f (x) < - 1 or f (x) > - 1

X Intercepts : (- 3, 0), Y Intercepts : (0, - \frac{3}{2})

Asymptotes : Vertical x = - 2, Horizontal y = - 1

Extreme Points : None

Interval Notation

Domain : (- \infty, - 2) \cup (- 2, 1) \cup (1, \infty)

Range : (- \infty, - \frac{4}{3}) \cup (- \frac{4}{3}, - 1) \cup (- 1, \infty)

Solution steps

Domain of

\frac{- ( x + 3 ) ( x - 1 )}{( x - 1 ) ( x + 2 )} : x < - 2 or - 2 < x < 1 or x > 1

Range of

\frac{- ( x + 3 ) ( x - 1 )}{( x - 1 ) ( x + 2 )} : f (x) < - \frac{4}{3} or - \frac{4}{3} < f (x) < - 1 or f (x) > - 1

Axis interception points of

\frac{- ( x + 3 ) ( x - 1 )}{( x - 1 ) ( x + 2 )} :

X Intercepts

: (- 3, 0),

Y Intercepts

: (0, - \frac{3}{2})

Asymptotes of

\frac{- ( x + 3 ) ( x - 1 )}{( x - 1 ) ( x + 2 )} :

Vertical

: x = - 2,

Horizontal

: y = - 1

Extreme Points of

\frac{- ( x + 3 ) ( x - 1 )}{( x - 1 ) ( x + 2 )} :

None

y = ln (x^{4} + 3 x^{2} + 1)

f (x) = \frac{2 + x}{x}

y = 2 x^{2} + 12 x

f (x) = 7 x + 30

y = - 5 lo g_{10} (2 x - 6) + 4

What is the f(x)=(-(x+3)(x-1))/((x-1)(x+2)) ?
The f(x)=(-(x+3)(x-1))/((x-1)(x+2)) is