What is the f(x)= 2/(x+2)+(1-sqrt(9-x^2))/3 ?

The f(x)= 2/(x+2)+(1-sqrt(9-x^2))/3 is

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f(x)= 2/(x+2)+(1-sqrt(9-x^2))/3

f (x) = \frac{2}{x + 2} + \frac{1 - 9 - x ^{2}}{3}

Domain : - 3 \leq x < - 2 or - 2 < x \leq 3

Range : f (x) \leq - \frac{5}{3} or f (x) \geq 0.03711 \dots

Y Intercepts : (0, \frac{1}{3})

Asymptotes : Vertical x = - 2

Extreme Points : Maximum (- 3, - \frac{5}{3}), Minimum (1.38905 \dots, 0.03711 \dots), Maximum (3, \frac{11}{15})

Interval Notation

Domain : [- 3, - 2) \cup (- 2, 3]

Range : (- \infty, - \frac{5}{3}] \cup [0.03711 \dots, \infty)

Solution steps

Domain of

\frac{2}{x + 2} + \frac{1 - 9 - x ^{2}}{3} : - 3 \leq x < - 2 or - 2 < x \leq 3

Range of

\frac{2}{x + 2} + \frac{1 - 9 - x ^{2}}{3} : f (x) \leq - \frac{5}{3} or f (x) \geq 0.03711 \dots

Axis interception points of

\frac{2}{x + 2} + \frac{1 - 9 - x ^{2}}{3} :

Y Intercepts

: (0, \frac{1}{3})

Asymptotes of

\frac{2}{x + 2} + \frac{1 - 9 - x ^{2}}{3} :

Vertical

: x = - 2

Extreme Points of

\frac{2}{x + 2} + \frac{1 - 9 - x ^{2}}{3} :

Maximum

(- 3, - \frac{5}{3}),

Minimum

(1.38905 \dots, 0.03711 \dots),

Maximum

(3, \frac{11}{15})

f (x) = \frac{- 1}{x + 1}

f (x) = \frac{2 - x - 2}{x ^{2} - 36}

f (x) = \frac{3 x ^{3} - 4 x ^{2} - 108 x + 139}{x ^{2} - 36}

h (x) = \frac{2 - x}{5 - x}

f (x) = 0.4 x^{2} + 2.7 x + 1

What is the f(x)= 2/(x+2)+(1-sqrt(9-x^2))/3 ?
The f(x)= 2/(x+2)+(1-sqrt(9-x^2))/3 is