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Popular >

y=(1+cos(2x))/(1-cos(2x))

Solution

y = \frac{1 + cos ( 2 x )}{1 - cos ( 2 x )}

Solution

Period : π

Domain : πn < x < π + πn

Range : f (x) \geq 0

X Intercepts : (\frac{π}{2} + πn, 0)

Asymptotes : Vertical x = πn

Extreme Points : Minimum (\frac{π}{2} + πn, 0)

+1

Interval Notation

Domain : (πn, π + πn)

Range : [0, \infty)

Solution steps

Periodicity of

\frac{1 + cos ( 2 x )}{1 - cos ( 2 x )} : π

Domain of

\frac{1 + cos ( 2 x )}{1 - cos ( 2 x )} : πn < x < π + πn

Range of

\frac{1 + cos ( 2 x )}{1 - cos ( 2 x )} : f (x) \geq 0

Axis interception points of

\frac{1 + cos ( 2 x )}{1 - cos ( 2 x )} :

X Intercepts

: (\frac{π}{2} + πn, 0)

Asymptotes of

\frac{1 + cos ( 2 x )}{1 - cos ( 2 x )} :

Vertical

: x = πn

Extreme Points of

\frac{1 + cos ( 2 x )}{1 - cos ( 2 x )} :

Minimum

(\frac{π}{2} + πn, 0)

Popular Examples

f(x)=cos(x)ln(1-x)

f (x) = cos (x) ln (1 - x)

y = (2)^{x}

f(x)=-2(x+3)^2-6

f (x) = - 2 (x + 3)^{2} - 6

f(x)=x^6+2x^4+6x^3+x^2+6x+9

f (x) = x^{6} + 2 x^{4} + 6 x^{3} + x^{2} + 6 x + 9

f(x)=(x^2-9)/(x^2)

f (x) = \frac{x ^{2} - 9}{x ^{2}}

Frequently Asked Questions (FAQ)

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