What is the f(x)=(x^3-3x^2+3x-1)/(x^2+x-2) ?

The f(x)=(x^3-3x^2+3x-1)/(x^2+x-2) is

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f(x)=(x^3-3x^2+3x-1)/(x^2+x-2)

f (x) = \frac{x ^{3} - 3 x ^{2} + 3 x - 1}{x ^{2} + x - 2}

Domain : x < - 2 or - 2 < x < 1 or x > 1

Range : f (x) \leq - 12 or f (x) > 0

Y Intercepts : (0, \frac{1}{2})

Asymptotes : Vertical x = - 2, Slant y = x - 4

Extreme Points : Maximum (- 5, - 12)

Interval Notation

Domain : (- \infty, - 2) \cup (- 2, 1) \cup (1, \infty)

Range : (- \infty, - 12] \cup (0, \infty)

Solution steps

Domain of

\frac{x ^{3} - 3 x ^{2} + 3 x - 1}{x ^{2} + x - 2} : x < - 2 or - 2 < x < 1 or x > 1

Range of

\frac{x ^{3} - 3 x ^{2} + 3 x - 1}{x ^{2} + x - 2} : f (x) \leq - 12 or f (x) > 0

Axis interception points of

\frac{x ^{3} - 3 x ^{2} + 3 x - 1}{x ^{2} + x - 2} :

Y Intercepts

: (0, \frac{1}{2})

Asymptotes of

\frac{x ^{3} - 3 x ^{2} + 3 x - 1}{x ^{2} + x - 2} :

Vertical

: x = - 2,

Slant

: y = x - 4

Extreme Points of

\frac{x ^{3} - 3 x ^{2} + 3 x - 1}{x ^{2} + x - 2} :

Maximum

(- 5, - 12)

f (x) = (2 x)^{2} - 1

f (x) = x^{\frac{3}{4}} - 4 x^{\frac{1}{4}}

f (n) = sin (\frac{nπ}{3})

f (n) = n^{2} + n - 1

f (x) = 8 x - 5

What is the f(x)=(x^3-3x^2+3x-1)/(x^2+x-2) ?
The f(x)=(x^3-3x^2+3x-1)/(x^2+x-2) is