What is the domain of f(x)=(sqrt(x+9))/(x-2) ?

The domain of f(x)=(sqrt(x+9))/(x-2) is -9 2

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domain of f(x)=(sqrt(x+9))/(x-2)

domain

f (x) = \frac{x + 9}{x - 2}

- 9 \leq x < 2 or x > 2

Interval Notation

[- 9, 2) \cup (2, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 9

Find undefined (singularity) points:

x = 2

Combine real regions and undefined points for final function domain

- 9 \leq x < 2 or x > 2

13 x - 11 y = 12

f (x) = x^{2} (x - 3)

\frac{2 x}{3 x - 1}

f (x) = 6 x + 12

What is the domain of f(x)=(sqrt(x+9))/(x-2) ?
The domain of f(x)=(sqrt(x+9))/(x-2) is -9<= x<2\lor x>2