What is the f(n)=(e^n+e^{-n})/(e^{2n)-1} ?

The f(n)=(e^n+e^{-n})/(e^{2n)-1} is

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f(n)=(e^n+e^{-n})/(e^{2n)-1}

f (n) = \frac{e ^{n} + e ^{- n}}{e ^{2 n} - 1}

Domain : n < 0 or n > 0

Intercepts : None

Asymptotes : Vertical n = 0, Horizontal y = 0

Extreme Points : None

Interval Notation

Domain : (- \infty, 0) \cup (0, \infty)

Solution steps

Domain of

\frac{e ^{n} + e ^{- n}}{e ^{2 n} - 1} : n < 0 or n > 0

Axis interception points of

\frac{e ^{n} + e ^{- n}}{e ^{2 n} - 1} :

None

Asymptotes of

\frac{e ^{n} + e ^{- n}}{e ^{2 n} - 1} :

Vertical

: n = 0,

Horizontal

: y = 0

Extreme Points of

\frac{e ^{n} + e ^{- n}}{e ^{2 n} - 1} :

None

y = 3 (x + 1)^{2}

f (x) = (x - 4) (x + 1)^{2}

f (θ) = θ - sin (θ)

f (x) = 2 x^{5} - 7 x^{3} + 4 x

f (x) = 7 x^{2} - 3 x + 10