What is the y= 3/8 x-1/8 sin(4x)+1/64 sin(8x) ?

The y= 3/8 x-1/8 sin(4x)+1/64 sin(8x) is

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y= 3/8 x-1/8 sin(4x)+1/64 sin(8x)

y = \frac{3}{8} x - \frac{1}{8} sin (4 x) + \frac{1}{64} sin (8 x)

Domain : - \infty < x < \infty

Range : - \infty < f (x) < \infty

Y Intercepts : (0, 0)

Asymptotes : None

Extreme Points : Minimum (\frac{πn}{2}, \frac{3 πn}{16} - \frac{1}{8} sin (2 πn) + \frac{1}{64} sin (4 πn))

Interval Notation

Domain : (- \infty, \infty)

Range : (- \infty, \infty)

Solution steps

Domain of

\frac{3}{8} x - \frac{1}{8} sin (4 x) + \frac{1}{64} sin (8 x) : - \infty < x < \infty

Range of

\frac{3}{8} x - \frac{1}{8} sin (4 x) + \frac{1}{64} sin (8 x) : - \infty < f (x) < \infty

Axis interception points of

\frac{3}{8} x - \frac{1}{8} sin (4 x) + \frac{1}{64} sin (8 x) :

Y Intercepts

: (0, 0)

Asymptotes of

\frac{3}{8} x - \frac{1}{8} sin (4 x) + \frac{1}{64} sin (8 x) :

None

Extreme Points of

\frac{3}{8} x - \frac{1}{8} sin (4 x) + \frac{1}{64} sin (8 x) :

Minimum

(\frac{πn}{2}, \frac{3 πn}{16} - \frac{1}{8} sin (2 πn) + \frac{1}{64} sin (4 πn))

f (x) = e^{x} arcsin (x)

h (x) = - lo g_{10} (3 x - 7) + 5

y = 5 x^{2} - 30 x + 95

f (r) = r^{2} + r + 1

y = lo g_{2} (x - 5)

What is the y= 3/8 x-1/8 sin(4x)+1/64 sin(8x) ?
The y= 3/8 x-1/8 sin(4x)+1/64 sin(8x) is