What is the f(x)=((2x+3)sqrt(x-3))/((x-8)^2) ?

The f(x)=((2x+3)sqrt(x-3))/((x-8)^2) is

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f(x)=((2x+3)sqrt(x-3))/((x-8)^2)

f (x) = \frac{( 2 x + 3 ) x - 3}{( x - 8 ) ^{2}}

Domain : 3 \leq x < 8 or x > 8

Range : f (x) \geq 0

X Intercepts : (3, 0)

Asymptotes : Vertical x = 8, Horizontal y = 0

Extreme Points : Minimum (3, 0)

Interval Notation

Domain : [3, 8) \cup (8, \infty)

Range : [0, \infty)

Solution steps

Domain of

\frac{( 2 x + 3 ) x - 3}{( x - 8 ) ^{2}} : 3 \leq x < 8 or x > 8

Range of

\frac{( 2 x + 3 ) x - 3}{( x - 8 ) ^{2}} : f (x) \geq 0

Axis interception points of

\frac{( 2 x + 3 ) x - 3}{( x - 8 ) ^{2}} :

X Intercepts

: (3, 0)

Asymptotes of

\frac{( 2 x + 3 ) x - 3}{( x - 8 ) ^{2}} :

Vertical

: x = 8,

Horizontal

: y = 0

Extreme Points of

\frac{( 2 x + 3 ) x - 3}{( x - 8 ) ^{2}} :

Minimum

(3, 0)

y = 5 x^{2} - 4 x - 8

y = \frac{x}{9 - x ^{2}}

y = - 8 cos (\frac{3 π}{2} x + 1)

f (x) = - 3 arccos (5 x + 9)

What is the f(x)=((2x+3)sqrt(x-3))/((x-8)^2) ?
The f(x)=((2x+3)sqrt(x-3))/((x-8)^2) is