What is the f(x)=-0.0556x^2+1.6661x-0.1612 ?

The f(x)=-0.0556x^2+1.6661x-0.1612 is

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f(x)=-0.0556x^2+1.6661x-0.1612

f (x) = - 0.0556 x^{2} + 1.6661 x - 0.1612

Domain : - \infty < x < \infty

Range : f (x) \leq 0

X Intercepts : (\frac{1.6661 - 2.74003833}{0.1112}, 0), (\frac{1.6661 + 2.74003833}{0.1112}, 0), Y Intercepts : (0, - 0.1612)

Vertex : Maximum (14.98291 \dots, 12.32031 \dots)

Inverse : - \frac{- 1.6661 + - 0.2224 x + 2.74003833}{0.1112}, - \frac{- 1.6661 - - 0.2224 x + 2.74003833}{0.1112}

Interval Notation

Domain : (- \infty, \infty)

Range : (- \infty, 0]

Solution steps

Domain of

- 0.0556 x^{2} + 1.6661 x - 0.1612 : - \infty < x < \infty

Range of

- 0.0556 x^{2} + 1.6661 x - 0.1612 : f (x) \leq 0

Axis interception points of

- 0.0556 x^{2} + 1.6661 x - 0.1612 :

X Intercepts

: (\frac{1.6661 - 2.74003833}{0.1112}, 0), (\frac{1.6661 + 2.74003833}{0.1112}, 0),

Y Intercepts

: (0, - 0.1612)

Vertex of

- 0.0556 x^{2} + 1.6661 x - 0.1612 :

Maximum

(14.98291 \dots, 12.32031 \dots)

Inverse of

- 0.0556 x^{2} + 1.6661 x - 0.1612 : - \frac{- 1.6661 + - 0.2224 x + 2.74003833}{0.1112}, - \frac{- 1.6661 - - 0.2224 x + 2.74003833}{0.1112}

f (1) = \frac{1}{x}

f (y) = y e^{y}

f (x) = \frac{( 9 x - 4 )}{( 4 x + 8 )}

y = 4 x^{2} - 25

y = \frac{10}{x ^{2}}

What is the f(x)=-0.0556x^2+1.6661x-0.1612 ?
The f(x)=-0.0556x^2+1.6661x-0.1612 is