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Popular >

f(t)=ln(2t-1)

Solution

f (t) = ln (2 t - 1)

Solution

Domain : t > \frac{1}{2}

Range : - \infty < f (t) < \infty

X Intercepts : (1, 0)

Asymptotes : Vertical t = \frac{1}{2}

Extreme Points : None

+1

Interval Notation

Domain : (\frac{1}{2}, \infty)

Range : (- \infty, \infty)

Solution steps

Domain of

ln (2 t - 1) : t > \frac{1}{2}

Range of

ln (2 t - 1) : - \infty < f (t) < \infty

Axis interception points of

ln (2 t - 1) :

X Intercepts

: (1, 0)

Asymptotes of

ln (2 t - 1) :

Vertical

: t = \frac{1}{2}

Extreme Points of

ln (2 t - 1) :

None

Popular Examples

y = \frac{5 x}{x + 2}

y = 3 x^{2} + 6 x - 24

f (x) = - 0.25 x^{2}

y = - \frac{1}{x} - 4

y = - \frac{1}{x} + 2

Frequently Asked Questions (FAQ)

What is the f(t)=ln(2t-1) ?
The f(t)=ln(2t-1) is