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Popular >

A={1/(n^2+4):n\in n}

Solution

A = {\frac{1}{n ^{2} + 4} : n \in n}

Solution

Domain : - \infty < n < \infty

Range : 0 < f (A) \leq \frac{1}{4}

Y Intercepts : (0, \frac{1}{4})

Asymptotes : Horizontal y = 0

Extreme Points : Maximum (0, \frac{1}{4})

+1

Interval Notation

Domain : (- \infty, \infty)

Range : (0, \frac{1}{4}]

Solution steps

Domain of

\frac{1}{n ^{2} + 4} : - \infty < n < \infty

Range of

\frac{1}{n ^{2} + 4} : 0 < f (A) \leq \frac{1}{4}

Axis interception points of

\frac{1}{n ^{2} + 4} :

Y Intercepts

: (0, \frac{1}{4})

Asymptotes of

\frac{1}{n ^{2} + 4} :

Horizontal

: y = 0

Extreme Points of

\frac{1}{n ^{2} + 4} :

Maximum

(0, \frac{1}{4})

Popular Examples

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f (x) = \frac{x ^{2} + 1}{2 x ^{2} - 3 x - 2}

P(t)=120t-0.4t^4+1000

P (t) = 120 t - 0.4 t^{4} + 1000

f (x) = x + \frac{8}{x}

f(x)=-8x*\sqrt[3]{x+2}

f(x)=5x^2(3x+2)(x-5)

f (x) = 5 x^{2} (3 x + 2) (x - 5)

Frequently Asked Questions (FAQ)

What is the A={1/(n^2+4):n\in n} ?
The A={1/(n^2+4):n\in n} is